# Wave Walker DSP

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Fourier Transform Convolution Property Derivation
November 17, 2021

#### Introduction

The convolution property of the Fourier transform states that the convolution of x(t) and h(t) is the product of the frequency-responses X(f) and H(f),

(1) #### Proof

The end result needs to be two Fourier transform integrals of x(t) and h(t) in order to arrive at (1). Start by writing the convolution using the integral

(2) Take the Fourier transform of (2)

(3) Expand the Fourier transform of (3) by writing out the integral,

(4) There are now two integrals over time, both t and which will form the basis for the two Fourier transforms. The variables dependent on t and need to be rearranged so their integrals are independent of one another. Start by separating the terms only dependent on by rearranging the terms in the right hand of (4),

(5) The variable is a problem because it has dependencies on both t and . Use a variable substitution

(6) such that

(7) As a result of (6),

(8) and

(9) The derivative because it is a constant within the integral over t in (5). Substituting (8) and (9) into (5),

(10) The exponential can be expanded as the product of two exponentials of and v,

(11) Substituting (11) into (10),

(12) Rearranging (12) into integrals of v and ,

(13) The two integrals are now Fourier transforms of x(t) and h(t),

(14) (15) Therefore as in (1).

#### Conclusion

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